A solid gold bar is pulled up from the hold of the sunken RMSTitanic.

(a)What happens to its volume as it goes from the pressure atthe ship to the lower pressure at the ocean's pressure?

(b) The pressure difference is proportional to the depth. Howmany times greater would the volume change have been had the shipbeen twice as deep?

(c) The bulk modulus of lead is one-fourth that of gold. Findthe ratio of the volume change of a solid lead bar to that of agold bar of equal volume for the same pressure change.

Answer :

Answer:

a) We see that the change in volume is less for a lower pressure

b) The change in volume would be double

c) The change in volume of lead is four times that of gol

Explanation:

The change in volume with the pressure given by the Balk module

       B = - P / (ΔV / V)

The minus sign is included so that the balk module is positive

a) let's clear the volume change

         ΔV = - P V / B

When repression decreases the pressure change is negative

        ΔV₂ = - P₀ V / B

We see that the change in volume is less for a lower pressure, so if the body is submerged when taking out the volume it increases

b)     P₁ = ρ g h

      ΔV₁ = - P₁ V / B

     ΔV₁ = - ρ g h

   

     P₂ = ρ g 2h

    ΔV₂ = - P₂ V / B

    Δv₂ = -ρ g 2h V / B

    ΔV₂ = 2 DV₁

The change in volume would be double

c) Calculate the volume change for material

     [tex]B_{Pb}[/tex] = ¼  [tex]B_{Au}[/tex]

    ΔV = -p V /  [tex]B_{Pb}[/tex]

    ΔV = P V 4 /  [tex]B_{Au}[/tex]  

    ΔV = 4 (-P V /  [tex]B_{Au}[/tex] )

The change in volume of lead is four times that of gold

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