Answer :
Answer:
[tex]\dfrac{K_m}{K_w}=0.734[/tex]
Explanation:
given,
weight of the man = 680 N
weight of the woman = 500 N
mass of man = [tex]\dfrac{680}{9.8}[/tex]
M_m = 69.4 Kg
mass of woman
= [tex]\dfrac{500}{9.8}[/tex]
M_w = 51 Kg
ratio of man's kinetic energy Km to that of the woman Kw
[tex]\dfrac{K_m}{K_w}=\dfrac{\dfrac{P_m^2}{2M_m}}{\dfrac{P_w^2}{2M_w}}[/tex]
momentum is same
[tex]\dfrac{K_m}{K_w}=\dfrac{2M_w}{2M_m}[/tex]
[tex]\dfrac{K_m}{K_w}=\dfrac{M_w}{M_m}[/tex]
[tex]\dfrac{K_m}{K_w}=\dfrac{51}{69.4}[/tex]
[tex]\dfrac{K_m}{K_w}=0.734[/tex]