Answer :

Answer:

[tex]g=16.28m/s^2[/tex]

Explanation:

The gravitational acceleration on the surface of the earth is

[tex]g_{e}=\frac{Gm_{e}}{R_{e}^2}[/tex]

where G is the universal gravitational constant, [tex]m_{e}[/tex] is the mass of earth, and [tex]R_{e}[/tex] is the radius of earth,

in general for any object the gravitational acceleration or gravity on its surface is:

[tex]g=\frac{Gm}{R^{2}}[/tex]

in this case we know that the mass is 1.66 times the mass of earth:

[tex]m=1.66*m_{e}[/tex]

and the radius is the same as for earth:

[tex]R=R_{e}[/tex]

so the gravity for this planet is

[tex]g=\frac{G(1.66m_{e})}{R_{e}^2}[/tex]

which can be written in the following form:

[tex]g=(1.66)\frac{Gm_{e}}{R_{e}^2}[/tex]

where we know that [tex]g_{e}=\frac{Gm_{e}}{R_{e}^2}[/tex] , so:

[tex]g=(1.66)g_{e}[/tex]

and the acceleration of gravity on earth is: [tex]g_{e}=9.81m/s^2[/tex]

so the acceleration or gravity on the planet is:

[tex]g=(1.66)(9.81m/s^2)\\g=16.28m/s^2[/tex]

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