Answered

A projectile is launched into the air with an initial speed of 40 m/s and a launch angle of 20° above the horizontal. The projectile lands on the ground five seconds later. Neglecting air resistance, calculate the projectile’s range and draw a projectile path.

Answer :

Explanation:

V=40m/s

Vy=V.sina=40.sin20=40 . 0.342=13.68m/s

Vx=V.cosa=40.cos20=40 . 0.766=30.64m/s

Projectile travels during 5 seconds and the ramge becomes:

x=V.t=30.64 . 5=153.2m

${teks-lihat-gambar} OrhanTurkeli

Other Questions