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A gun with a muzzle velocity of 1500 feet per second is fired at an angle of 6 degrees with the horizontal. Find the vertical and horizontal components of the velocity to the nearest whole number.

Answer :

Answer:

The vertical component of velocity is 156 feet per second

The horizontal component of velocity 1491 feet per second .

Step-by-step explanation:

Given as :

The velocity of gun = v = 1500 feet per sec

The angle made by gun with horizontal = Ф = 6°

Let The vertical component of velocity = [tex]v__y[/tex]

Let The horizontal component of velocity = [tex]v__x[/tex]

Now, According to question

The vertical component of velocity = v sin Ф

i.e  [tex]v__y[/tex] = v sin Ф

Or , [tex]v__y[/tex] = 1500 ft/sec × sin 6°

Or , [tex]v__y[/tex] = 1500 ft/sec × 0.104

∴  [tex]v__y[/tex] = 156 feet per second

So, The vertical component of velocity = [tex]v__y[/tex] = 156 feet per second

Now, Again

The horizontal component of velocity = v cos Ф

i.e  [tex]v__x[/tex] = v cos Ф

Or , [tex]v__x[/tex] = 1500 ft/sec × cos 6°

Or , [tex]v__x[/tex] = 1500 ft/sec × 0.994

∴  [tex]v__x[/tex] = 1491 feet per second

So, The horizontal component of velocity = [tex]v__y[/tex] = 1491 feet per second

Hence,The vertical component of velocity is 156 feet per second

And The horizontal component of velocity 1491 feet per second . Answer

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