PLEASE HELP ASAP!!! timed and will mark brainliest !!

The first graph is the solution for [tex]y=\sqrt[3]{x-3}[/tex].
Step-by-step explanation:
The general form of cube root function [tex]y =a\sqrt[3]{x-h} +k[/tex].
In cube root graphing, (h,k) will mark where the curve bends.
The parent function is [tex]y= \sqrt[3]{x}[/tex].
Since the parent fucntion had no (h,k) value then the curve bends at the point (0,0).
Refer the first graph is the graph of the parent function.
The value for [tex]y= \sqrt[3]{x}[/tex] is same as [tex]y=x^{3}[/tex] .
For [tex]y=\sqrt[3]{x-3}[/tex], the (h,k) value is(3,0).
∴ The curve bends at the point (3,0) i.e. horizontally moved from the point (0,0).
Second graph is the graph for function [tex]y=\sqrt[3]{x-3}[/tex].