a ladder 8ft long resting against a house makes a 60 degree
angle with the ground. how far up does the house reach? give answer
in terms of radicals with the radical in the numerator.

Answer :

Answer:

4√3 feet

Step-by-step explanation:

Here, a ladder is resting against a house makes a 60° with the ground,

Consider x be the distance of the top of ladder from the foot of house and y be the distance of bottom of ladder from the house. ( shown in the below diagram )

Using trigonometric ratio,

[tex]\sin 60^{\circ}=\frac{\text{Distance of top of ladder from the bottom of house}}{\text{Length of ladder}}[/tex]

We have, length of ladder = 8 ft,

[tex]\sin 60^{\circ}=\frac{x}{8}[/tex]

[tex]\frac{\sqrt{3}}{2}=\frac{x}{8}[/tex]

[tex]8\sqrt{3} = 2x[/tex]

[tex]4\sqrt{3}=x[/tex]

Hence, the house would reach 4√3 feet up.

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