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The transmutation of a radioactive uranium isotope, 234/92 U, into a radon isotope, 222/86 Rn, involves a series of three nuclear reactions. At the end of the first reaction, a thorium isotope, 230/90 Th, is formed and at the end of the second reaction, a radium isotope, 226/88 Ra, is formed. In both the reactions, an alpha particle is emitted. Write the balanced equations for the three successive nuclear reactions. Please show all work.

The transmutation of a radioactive uranium isotope, 234/92 U, into a radon isotope, 222/86 Rn, involves a series of three nuclear reactions. At the end of the f class=
The transmutation of a radioactive uranium isotope, 234/92 U, into a radon isotope, 222/86 Rn, involves a series of three nuclear reactions. At the end of the f class=
The transmutation of a radioactive uranium isotope, 234/92 U, into a radon isotope, 222/86 Rn, involves a series of three nuclear reactions. At the end of the f class=
The transmutation of a radioactive uranium isotope, 234/92 U, into a radon isotope, 222/86 Rn, involves a series of three nuclear reactions. At the end of the f class=

Answer :

praisedjansi

Answer:

The answer is 26/98 how i did this is i divided them mulitiplyed well i cant really explain it but im pretty dure its right

Explanation:

Answer : The balanced equations for the three successive nuclear reactions are:

First reaction will be:                

[tex]_{92}^{234}\textrm{U}\rightarrow _{90}^{230}Th+_2^4He[/tex]

Second reaction will be:                  

[tex]_{90}^{230}\textrm{Th}\rightarrow _{88}^{226}Ra+_2^4He[/tex]

Third reaction will be:                    

[tex]_{88}^{226}\textrm{Ra}\rightarrow _{86}^{222}Rn+_2^4He[/tex]

Explanation :

Alpha decay : In this process, alpha particles is emitted when a heavier nuclei decays into lighter nuclei. The alpha particle released has a charge of +2 units.

The general representation of alpha decay reaction is:

[tex]_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}Y+_2^4\alpha[/tex]

The balanced equations for the three successive nuclear reactions are:

First reaction will be:                

[tex]_{92}^{234}\textrm{U}\rightarrow _{90}^{230}Th+_2^4He[/tex]

Second reaction will be:                  

[tex]_{90}^{230}\textrm{Th}\rightarrow _{88}^{226}Ra+_2^4He[/tex]

Third reaction will be:                    

[tex]_{88}^{226}\textrm{Ra}\rightarrow _{86}^{222}Rn+_2^4He[/tex]

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