Answer :
Answer:
80%
Step-by-step explanation:
Let the first number be "100" and the other number be "100" as well.
Their normal product would be:
100 * 100 = 10,000
Now, we need to decrease one by 75% and another by 20%. First, let's convert the percentages to decimals. Shown below:
75% = 75/100 = 0.75
20% = 20/100 = 0.2
First number is "100", so decrease it by 75% to get:
100 - 0.75(100)
= 100 - 75
= 25
Next number is also "100", so decrease it by 20% to get:
100 - 0.2(100)
= 100 - 20
= 80
The new product would eb:
80 * 25 = 2000
Original Product = 10,000
New Product = 2000
To find percentage decrease, we use the formula:
[tex]\frac{New-Original}{Original}*100[/tex]
Lets substitute and find the answer:
[tex]\frac{New-Original}{Original}*100\\\frac{2000-10000}{10000}*100=80[/tex]
So, the new product is 80% decreased
The product of two numbers will decrease by 70%
Let the numbers be x and y.
So, the product of x and y is represented as: xy
If x is decreased by 75%, then it becomes x(1 - 75%)
If y is increased by 20%, then it becomes y(1 + 20%)
So, the product of the new numbers is:
[tex]Product= x(1 - 75\%) \times y(1 +20\%)[/tex]
Express percentage as decimals
[tex]Product= x(1 - 0.75) \times y(1 +0.20)[/tex]
This gives
[tex]Product= x(0.25) \times y(1.20)[/tex]
Rewrite the above equation as:
[tex]Product= 0.25x \times 1.20y[/tex]
Evaluate the products
[tex]Product= 0.3xy[/tex]
Rewrite as:
[tex]Product= xy(0.3)[/tex]
Express 0.3 as 1- 0.7
[tex]Product= xy(1 - 0.7)[/tex]
Express 0.7 as percentage
[tex]Product= xy(1 - 70\%)[/tex]
Hence, the product of two numbers will decrease by 70%
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