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What is the center and radius of the circle with equation(x+1)2+y2=81?

Question 1 options:

center: (1,0) ; radius: 81


center: (-1,0) ; radius: 81


center: (-1,0) ; radius: 9


center: (1,0) ; radius: 9

Answer :

calculista

Answer:

center: (-1,0) ; radius: 9

Step-by-step explanation:

we know that

The equation of a circle in center radius form is equal to

[tex](x-h)^2+(y-k)^2=r^2[/tex]

where

(h,k) is the center of the circle

r is the radius of the circle

In this problem we have

[tex](x+1)^2+y^2=81[/tex]

so

The center (h,k) is the point  [tex](-1,0)[/tex]

and

the radius

[tex]r^2=81\\r=9\ units[/tex]

therefore

center: (-1,0) ; radius: 9

Answer:Center:(-1,0)

Radius:9

Step-by-step explanation:

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