Answered

"What is the approximate centripetal acceleration of an object (mass = 50 g) on the end of an 80-cm string rotating at a constant rate of 2 times a second?"

Answer :

Answer:[tex]a_c=126.36 m/s^2[/tex]

Explanation:

Given

mass of object [tex]m=50 gm[/tex]

length of string [tex]L=80 cm[/tex]

Angular frequency [tex]\omega[/tex] will be [tex]\frac{4\pi}{1}[/tex] rad/s because it completing 2 complete circle in 1 sec

In rotation object turned [tex]2\pi[/tex] rad so for 2 rotation it will be [tex]4\pi [/tex]

centripetal acceleration is the inward acceleration experiences by an object when it moves in a circular path and it is given by

[tex]a_c=\omega ^2\times L[/tex]

[tex]a_c=(4\pi )^2\times 0.8[/tex]

[tex]a_c=126.36 m/s^2[/tex]

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