Answer :
Option A
The restaurant Manager can afford at most 10 employees for the day
Solution:
Given that restaurant manager can spend at most $600 a day for operating costs and payroll
It costs $100 each day to operate the bank and $50 dollars a day for each employee
The given inequality is:
[tex]50x + 100\leq 600[/tex]
Where , "x" is the number of employees per day
Let us solve the inequality for "x"
[tex]50x + 100\leq 600[/tex]
Add -100 on both sides of inequality
[tex]50x + 100 - 100\leq 600 - 100\\\\50x\leq 500[/tex]
Divide by 50 on both sides of inequality
[tex]\frac{50x}{50}\leq \frac{500}{50}\\\\x\leq 10[/tex]
Hence the restaurant Manager can afford at most 10 employees for the day
Thus option A is correct