Answer :
Answer:
(a) 5.38 m/s²
(b) 188.004 m
(c) 56.49 m/s.
Explanation:
(a) Acceleration: This is the rate of change of velocity. The S.I unit of acceleration is m/s².
Acceleration can be represented as,
a = v-u/t ..................... Equation 1
Where a = acceleration, v = velocity, t = time
Given: v = 45 m/s, u = 0 m/s ( from rest) t = 8.36 s.
Substituting into equation 1,
a = 45/8.36
a = 5.38 m/s²
Thus the acceleration of the car = 5.38 m/s²
(b) S = ut + 1/2at² ......................... Equation 2
Where S = distance, u = initial velocity, a = acceleration, t = time.
Given: u = 0 m/s (at rest), t = 8.36 s, a = 5.38 m/s²
Substituting into equation 2
S = 0(8.36) + 1/2(5.38)(8.36)²
S = 2.69(69.89)
S = 188.004 m
(c) Speed (v)
v = u + at...................... Equation 3
Given: u = 0 m/s (at rest), a = 5.38 m/s², t = 10.5 s.
Substituting into equation 3
v = 0 + 5.38(10.5)
v = 56.49 m/s.