Answer :
Explanation:
The given data is as follows.
[tex]P_{atm}[/tex] = 98.70 kPa = 98700 Pa,
T = [tex]30^{o}C[/tex] = (30 + 273) K = 303 K
height (h) = 30 mm = 0.03 m (as 1 m = 100 mm)
Density = 13.534 g/mL = [tex]13.534 g/mL \times \frac{10^{6}cm^{3}}{1 m^{3}} \times \frac{1 kg}{1000 g}[/tex]
= 13534 [tex]kg/m^{3}[/tex]
The relation between pressure and atmospheric pressure is as follows.
P = [tex]P_{atm} + \rho gh[/tex]
Putting the given values into the above formula as follows.
P = [tex]P_{atm} + \rho gh[/tex]
= [tex]98700 Pa + 13534 \times 9.81 \times 0.03 m[/tex]
= 102683.05 Pa
= 102.68 kPa
thus, we can conclude that the pressure of the given methane gas is 102.68 kPa.