Answer :
Fraction of students left-handed: [tex]\frac{3}{25}[/tex]
There are more right-handed students
Step-by-step explanation:
To solve the problem, we call:
[tex]p(L)[/tex] the fraction of students in the class that are left-handed
[tex]p(R)[/tex] the fraction of students in the class that are right-handed
We know that:
[tex]p(L) = 12\%[/tex] is the fraction of students which are left-handed
we can convert this value into fractional form dividing by 100:
[tex]p(L)=\frac{12}{100}[/tex]
Simplifying by 4,
[tex]p(L)=\frac{3}{25}[/tex]
We also know that
[tex]p(L)+p(R)=1[/tex], because the fraction of students that are either left or right-handed must be 100%
Therefore, the fraction of students that are right-handed is
[tex]p(R)=1-p(L)=1-\frac{3}{25}=\frac{22}{25}[/tex]
Therefore, there are more right-handed than left-handed students.
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