Answer :
Answer:
4.63 g/mL is the density of uranium hexafluoride.
Explanation:
Mass of an uranium hexafluoride , m= [tex]2.25\times 10^8 kg=2.25\times 10^8\times 1000 g=2.25\times 10^{11} g[/tex]
1 kg = 1000 g
Volume of drum in which uranium hexafluoride was stored = [tex]1.62\times 10^6 L=1.62\times 10^9 mL[/tex]
1 L = 1000 mL
Volume of uranium hexafluoride stored in 30 drums = V
[tex]V=30\times 1.62\times 10^9 mL[/tex]
Density of an uranium hexafluoride =d
[tex]d=\frac{m}{V}=\frac{2.25\times 10^{11} g}{30\times 1.62\times 10^9 mL}[/tex]
[tex]d=4.63 g/mL[/tex]
4.63 g/mL is the density of uranium hexafluoride.