Answer :
The width of rectangle is [tex]2\frac{1}{4}[/tex] cm and length is [tex]5\frac{5}{12}[/tex] cm.
Step-by-step explanation:
Let,
Width of rectangle = w
Length of rectangle = [tex]w+3\frac{1}{6}=w+\frac{19}{6}[/tex]
Perimeter of rectangle = [tex]15\frac{1}{3}=\frac{46}{3}[/tex] cm
Perimeter = 2(Length + Width)
[tex]\frac{46}{3}=2(w+\frac{19}{6}+w)\\\\\frac{46}{3}=2(2w+\frac{19}{6})\\\\\frac{46}{3}=4w+\frac{19}{3}\\\\4w+\frac{19}{3}=\frac{46}{3}\\\\4w=\frac{46}{3}-\frac{19}{3}\\\\\ 4w=\frac{46-19}{3}\\\\4w=\frac{27}{3}\\\\4w=9[/tex]
Dividing both sides by 4
[tex]\frac{4w}{4}=\frac{9}{4}\\\\w=\frac{9}{4}[/tex]
Width of rectangle = [tex]\frac{9}{4}=2\frac{1}{4}\ cm[/tex]
[tex]Length = w+\frac{19}{6}=\frac{9}{4}+\frac{19}{6}\\\\Length = \frac{27+38}{12}=\frac{65}{12}\\\\Length=5\frac{5}{12}\ cm[/tex]
The width of rectangle is [tex]2\frac{1}{4}[/tex] cm and length is [tex]5\frac{5}{12}[/tex] cm.
Keywords: rectangle, perimeter
Learn more about perimeter at:
- brainly.com/question/12613605
- brainly.com/question/12700460
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