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In preparing to shoot an arrow, an archer pulls a bow string back 0.420 m by exerting a force that increases uniformly from 0 to 230 N. What is the equivalent spring constant of the bow? Answer in units of N/m.

Answer :

Answer:

spring constant will be 547.619 N /m

Explanation:

We have given that force exerted if uniformly from 0 to 230 N

So exerted force F = 230 N

String is stretched by 0.420 m due to applying force

So x = 0.420 m

We have to find the spring constant in N/m

We know that stretched force is given by

[tex]F=Kx[/tex] , here K is spring constant and x is stretched length

So [tex]230=K\times 0.420[/tex]

[tex]K=\frac{230}{0.420}=547.619N/m[/tex]

So spring constant will be 547.619 N /m

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