Answer :

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Factor by grouping
[tex]2p^3 + 6p^2 + 3p + 9[/tex]
[tex]2 p^3+6 p^2+3 p+9=\left(2 p^3+6 p^2\right)+(3 p+9)=\left(2 p^2\right) (p+3)+3 (p+3)[/tex]
[tex]2 p^2 (p+3)+3 (p+3)[/tex]
[tex](p+3) \left(2 p^2+3\right)[/tex]

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