Answer :
Answer:
Josh reaches at [tex]\dfrac{h}{9}[/tex] height.
(g) is correct option
Explanation:
Given that,
Mass of martin = m
Mass of josh m'= 2m
Martin and Paul are skateboarding in a large semicircular halfpipe. Martin starts out from rest at a height h and collides with Paul standing at the bottom. Martin and Paul have about the same mass. After the collision,
We need to calculate the speed before the collision
Using conservation of energy
[tex]mgh=\dfrac{1}{2}mv^2[/tex]
[tex]v=\dfrac{2gh}[/tex]
We need to calculate the final speed after collision
Using conservation of momentum
[tex]mv_{i}=(m+2m)v_{f}[/tex]
Put the value into the formula
[tex]v_{f}=\dfrac{\sqrt{2gh}}{3}[/tex]
We need to calculate the height
Using conservation of energy
[tex]\dfrac{1}{2}\times m\times v^2=mgH[/tex]
Put the value into the formula
[tex]\dfrac{1}{2}\times 3m\times(\dfrac{2gh}{9})=3mgH[/tex]
[tex]H=\dfrac{h}{9}[/tex]
Hence, Josh reaches at [tex]\dfrac{h}{9}[/tex] height.