Answer :
Magnitude of their sum, F = 8.61 N
Explanation:
Resultant, R of two vectors P and Q is given by,
[tex]R=\sqrt{P^2+Q^2+2PQcos\theta }[/tex]
Here P = 4.52 N
Q = 7.33 N
θ = 90°
Substituting
[tex]R=\sqrt{4.52^2+7.33^2+2\times 4.52\times 7.33\times cos90 }\\\\R=8.61N[/tex]
Magnitude of their sum, F = 8.61 N