Answer :
Answer:
Acceleration will be [tex]5706.77rad/sec^2[/tex]
So option (D) will be correct answer
Explanation:
We have given angular speed of the electrical motor [tex]\omega =2695rpm[/tex]
We have to change this angular speed in rad/sec for further calculation
So [tex]\omega =2695rpm=2695\times \frac{2\pi }{60}=282.2197rad/sec[/tex]
Armature radius is given r = 7.165 cm = 0.07165 m
We have to find the acceleration of edge of motor
Acceleration is given by [tex]a=\omega ^2r=282.2197^2\times 0.07165=5706.77rad/sec^2[/tex]
So acceleration will be [tex]5706.77rad/sec^2[/tex]
So option (D) will be correct answer
The acceleration of the edge of rotor will be "5707 rad/s²".
Given:
Radius,
- r = 7.165 cm
or,
= 0.07165 m
Angular speed,
- [tex]\omega[/tex] = [tex]2695.0 \ rpm[/tex]
or,
= [tex]2695\times \frac{2 \pi}{60}[/tex]
= [tex]282.2197 \ rad/sec[/tex]
Now,
The acceleration will be:
→ [tex]a = \omega^2 r[/tex]
[tex]= 282.2197^2\times 0.07165[/tex]
[tex]= 5706.77 \ rad/sec^2[/tex]
Thus the above answer is right.
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