Let f(x) = 2x + 5 and g(x) = x^2 - 3x + 2
a. 3f(x) - 2
b. f(x) - 2g(x)
c. 5f(x)/g(x)

Answer:
The answer to your question is below
Step-by-step explanation:
f(x) = 2x + 5
To solve letter a, just multiply each term of f(x) by 3 and subtract 2.
a) 3f(x) - 2 = 3(2x + 5) - 2
= 6x + 15 - 2
= 6x + 13
To f(x) subtract twice g(x)
b) f(x) - 2g(x) = 2x + 5 - 2(x² - 3x + 2)
= 2x + 5 - 2x² + 6x - 4
= -2x² + 8x + 1
Multiply 5 by each term of f(x) and divide it by g(x)
c) [tex]\frac{5f(x)}{g(x)} = \frac{5(2x + 5)}{x^{2} - 3x + 2}[/tex]
= [tex]\frac{10x + 25}{x^{2}-3x + 2}[/tex]