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a scaffold that weighs 400 n supports two painters, one 500 n and the other 400 n. the tension in the rope on the left is 800 n. what is the magnitude of the tension in the rope on the right

Answer :

Answer:

The magnitude of the tension in the rope on the right is 500 N.

Explanation:

Given that,

Weight of scaffold= 400 N

Weight of first painter = 500 N

Weight of second painter = 400 N

Tension in the rope = 800 N

According to figure,

We need to calculate the magnitude of the tension in the rope on the right

Using balance equation

[tex]T_{r}+T=W_{p}+W_{sp}+W_{s}[/tex]

Where, [tex]T_{r}[/tex]=Tension on left side

[tex]W_{r}[/tex]=weight of first painter

[tex]W_{sr}[/tex]=weight of second painter

[tex]W_{r}[/tex]=weight of scaffold

Put the value in the equation

[tex]800+T=400+500+400[/tex]

[tex]T=1300-800[/tex]

[tex]T=500\ N[/tex]

Hence, The magnitude of the tension in the rope on the right is 500 N.

${teks-lihat-gambar} CarliReifsteck

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