Answer:
The height of deepness of submarine is 424.1 feet
Step-by-step explanation:
Given as :
The angle at which submarine drives of the surface of water = Ф = 13°
The speed at which submarine travel = s = 760 feet per minute
Let The height of deepness of submarine = h feet
The time taken to reach that deepness = t = 5 minutes
According to question
The height of deepness of submarine = [tex]\dfrac{\textrm speed}{\textrm time}[/tex]
i.e h × cos(90 - Ф) = [tex]\dfrac{s}{t}[/tex]
Or, h × Sin(Ф) = [tex]\dfrac{\textrm 760 feet per min}{8 min}[/tex]
Or, h × Sin(13°) = 95 feet
Or, h × 0.224 = 95 feet
∴ h = [tex]\dfrac{95}{0.224}[/tex]
i.e h = 424.10 feet
So, The height of deepness of submarine = h = 424.10 feet
Hence, The height of deepness of submarine is 424.1 feet Answer