Answer:
The mass of strontium iodate = 496.07 grams
Explanation:
The balanced equation for the reaction is :
[tex]2RbIO3+Sr(NO_{3})_{2}\rightarrow 2RbNO_{3}+Sr(IO_{3})_{2}[/tex]
Molar mass = mass of substance present in 1 mole of the compound , is called the molar mass.
Here RbIO3 = rubidium iodate
Sr(NO3)2 = strontium nitrate
Sr(IO3)2 = strontium iodate
Molar mass of Sr(NO3)2 = 211.63 g/mol
1 mole Sr(NO3)2 = 211.63 g
Molar mass of Sr(IO3)2 = 437.43 g/mol
1 mole of Sr(IO3)2 = 437.43 g
According to the balanced equation ,
2 mole RbIO3 = 1 mole Sr(NO3)2 = 2 mole RbNO3 = 1 mole Sr(IO3)2
Hence
1 mole of Sr(NO3)2 is producing = 1 mole Sr(IO3)2
211.63 gram of Sr(NO3)2 will produce = 437.43 gram Sr(IO3)2
1 gram of Sr(NO3)2 will produce:
[tex]=\frac{437.43}{211.63}[/tex]
240 grams of Sr(NO3)2 will produce:
[tex]=\frac{437.43}{211.63}\times 240[/tex] grams of Sr(IO3)2
= 496.07 grams of Sr(IO3)2
The mass of strontium iodate = 496.07 grams
Molar mass calculation :
Sr(NO3)2 = Mass of Sr + 2(Mass of N)+ 6(Mass of O)
= 87.62 +2(14)+6(16)
=211.63 gram/mole