Answer :
The reaction of 45 g of glucose will produce 66 g of CO2
Explanation:
Here is the balanced equation:
C6H12O6+6O2→6CO2+6H2O
Since the molar mass of glucose is 180 g, the 45 g given mass in this problem is
no. of moles = 45g divided by 180g=0.25 mole
The equation tells us there are 6 moles of CO2 produced for each 1 mole of glucose that reacts. There fore, we will obtain
6×0.25=1.50moles of C6H12O6
Finally, converting to mass
1.50moles×44g mole
=66g