Answer :
Answer:
[tex]v=\sqrt{2gh}[/tex]
Explanation:
We could use conversation of energy. Total distance the stone will cover will be
[tex]h=\frac{1}{2} g t^{2}[/tex]
the Final velocity will be
[tex]v=gt\\v=g\sqrt{\frac{2h}{g} }\\ v=\sqrt{2gh}[/tex]
The velocity will be [tex]v=\sqrt{2gh} [/tex]
Conversation of energy:
It states that the energy of interacting bodies or particles in a closed system remains constant.
It is given that:
A stone is dropped from rest at an initial height h above the surface of the earth.
To show:
The speed with which it strikes the ground
So, from conservation of Energy;
Total distance the stone will cover = [tex]h=\frac{1}{2} gt^2\\\\ [/tex]
The final velocity will be:
[tex]v=gt\\\\ v=g\sqrt{\frac{2h}{g} } \\\\ v=\sqrt{2gh} [/tex]
Learn more:
brainly.com/question/6237128