Answered

A 50.0 g sample of an unknown metal at 100.0∘C is placed in 500. g of water at 25.00∘C. The final temperature of the system is 27.40∘C. What is the specific heat of the metal in joules per gram degree Celsius?

Answer :

joseaaronlara

Answer:

The answer to your question is      C = 1.38 J/g°C

Explanation:

Data

Sample                                   Water

mass = ms = 50 g                   mass = mw = 500 g

T1 = 100°C                                T1 = 25°C

T2 = 27.4°C                              T2 = 27.4°C

C = ?                                          C = 4.18 J/g°C

Formula

             - Heat release  = Heat absorbe

             - msC (T2 - T1) = mwC(T2 - T1)

Substitution

             -50(27.4 - 100)C = 500(4.18)(27.4 - 25)

Simplification

             -50 (-72.6)C = 500(4.18)(2.4)

                    3630C = 5016

Solve for C

                             C = 5016 / 3630

Result

                             C = 1.38 J/g°C

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