Answer :
Answer:
1,070.41 grams of DDT will be formed .Explanation:
1) [tex]2 C_6H_5Cl + C_2HOCl_3\rightarrow C_{14}H_9Cl_5 + H_2O[/tex]
Moles of chlorobenzene = [tex]\frac{1197 g}{112.5 g/mol}=10.64 mol[/tex]
According to reaction, 2 moles of chloro benzene reacts with 1 mole of chloral . Then 10.64 moles of chloro benzene will react with :
[tex]\frac{1}{2}\times 10.64 mol=5.32 mole[/tex] of chloral
2) Moles of chloral = [tex]\frac{456 g}{147.5 g/mol}=3.0915 mol[/tex]
According to reaction, 1 moles of chloral reacts with 2 mole of chlorobenzene . Then 3.0915 moles of chloral will react with :
[tex]\frac{2}{1}\times 3.0915 mol=6.1830 mol[/tex] of chloro benzene
As we can see that chloral is in limiting amount and chloro benzene is in excessive amount. So, amount of DDT will depend upon amount of chloral.
According to reaction, 1 mole chloral gives 1 mole DDT.Then 3.0195 moles of chloral will give :
[tex]\frac{1}{1}\times 3.0195 mol=3.0195 mol[/tex]
Mass of 3.0195 moles of DTT :
3.0195 mol × 354.5 g/mol = 1,070.41 g
1,070.41 grams of DDT will be formed .