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An airplane needs to reach a velocity of 203.0 km/h to take off. On a 2000 m runway, what is the minimum acceleration necessary for the plane to take flight?

Answer :

jenicamuchemwa

Answer:

1.59 m/s²

Step-by-step explanation:

Acceleration = change in Velocity over time. Mathematically it is represented as Δv/Δt

Given values in the question:

  • Final velocity 203.0 km/h which is equal to (203/3.6)m/s = 56.39 m/s
  • distance 2000 m
  • Initial velocity is 0 m/s

To use the equation for acceleration time is needed.

velocity= distance/time

(203/3.6) = 2000/time  mltiplying both sides by time

(203/3.6) x time = 2000 making time subject of the formula

time = 2000/(203/3.6)

time = 35.47 seconds

Substituting into the acceleration equation

acceleration =Δv/Δt

                      =(56.39- 0)/35.47

                       = 56.39/35.47

                       =1.59 m/s²

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