Answer :
The angle of refraction is greater than the angle of incidence
What will be the angle of refraction?
From Snell's law of refraction, we can write the equation
[tex]n_1sin\theta_1= n_2sin\theta_2[/tex]
here;
[tex]n_1[/tex] is the refractive index of incidence medium
[tex]\theta_1[/tex]is the angle of incidence
[tex]n_2[/tex]is Refractive index of refraction medium
[tex]\theta_2[/tex] is the angle of refraction
Its is given [tex]n_1[/tex] = 1.5 and [tex]n_2[/tex] = 1.33
Thus;
[tex]1.5sin\theta_1=1.33sin\theta_2[/tex]
by rearranging the equation we have;
[tex]\dfrac{Sin\theta_1}{Sin\theta_2} =\dfrac{1.33}{1.5}[/tex]
We know from trigonometry, that sin 0 = 0 and sin 90 = 1. So, as θ approaches 0°,
The value of sinθ decreases while as it approaches 90°, the value of sinθ increases.
Thus, by inspection, we can say that the value of the denominator is higher than the numerator.
Thus, θ2 is greater than θ1
Thus the angle of refraction is greater than the angle of incidence
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