help pleaseeeeeeeeeeeeeeeeeeee

Answer: Second option.
Step-by-step explanation:
You can divide the arrow into two figures: A triangle and a rectangle (See the figure attached).
The area of a triangle can be calculated wit this formula:
[tex]A_t=\frac{bh}{2}[/tex]
Where "b" is the base of the triangle and "h" is the height.
In this case, you can identify that:
[tex]b=6\ in\\\\h=8\ in-5\ in=3\ in[/tex]
Therefore, you get that the area of the triangle is:
[tex]A_t=\frac{6\ in*3\ in}{2}\\\\A_t=9\ in^2[/tex]
The area of a rectangle can be calculated with this formula:
[tex]A_r=lw[/tex]
Where "l" is the lenght of the rectangle and "w" is the width.
In this case:
[tex]l=5\ in\\\\w=4\ in[/tex]
Therefore, its area is:
[tex]A_r=5\ in*4\ in\\\\A_r=20\ in^2[/tex]
And the total area of the arrow is:
[tex]A_T=9\ in^2+20\ in^2\\\\A_T=29\ in^2[/tex]