Answer :
Answer:
Explanation:
Given
Electric field strength [tex]E=531\ N/C[/tex]
mass of electron [tex]m_e=9.1\times 10^{-31}\ kg[/tex]
charge on electron [tex]q=-1.6\times 10^{-27}\ kg[/tex]
Force on a charge particle inside an Electric field is given by
[tex]F=q\times E[/tex]
[tex]F=1.6\times 10^{-27}\times 531=849.6\times 10^{-27}\ N[/tex]
acceleration is given by [tex]a=\frac{F}{m}[/tex]
[tex]a=\frac{849.6\times 10^{-27}}{9.1\times 10^{-31}}[/tex]
[tex]a=93.36\times 10^4\ m/s^2[/tex]
Answer:
Explanation:
mass of electron, m = 9.1 x 10^-31 kg
charge of electron, q = 1.6 x 10^-19 C
Electric field, E = 531 N/C
Force on electron, F = q x E
Where, E is the electric field strength
F = 1.6 x 10^-19 x 531
F = 8.496 x 10^-17 N
Let a be the acceleration of the electron.
a = Force / mass
a = (8.496 x 10^-17) / (9.1 x 10^-31)
a = 9.34 x 10^13 m/s²