Answer:
The factors of the polynomial: (b⁴ - 2)(b² - 3)
Step-by-step explanation:
The given polynomial is: [tex]$ \textbf{b}^{\textbf{6}} \textbf{-3b}^{\textbf{4}} \textbf{-2b}^{\textbf{2}} \textbf{+ 6} $[/tex]
We can factor the given polynomial by grouping.
We get: [tex]$ \{ b^6 - 3b^4\} + \{2b^2 + 6\} $[/tex]
[tex]$ = b^4 (b^2 - 3) -2(b^2 - 3) $[/tex]
Taking (b² - 3) common outside, we get:
[tex]$ = \{b^2 - 3\} \{b^4 - 2\} $[/tex]
Hence the polynomial [tex]$ b^6 - 3b^4 - b^2 + 6 $[/tex] can be factored as [tex]$ (b^4 - 2)(b^2 - 3) $[/tex].
Hence, the answer.