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Physics

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A 0.250 kg mass is attached to a spring with k=18.9 N/m. At the equilibrium position, it moves 2.89 m/s. What is the amplitude of the oscillation? (Unit=m)

Answer :

rahulnair123437 rahulnair123437

Today at 1:02 AM

Amplitude of oscillation is 0.33 m

Explanation:

Amplitude is the maximum displacement of points on a wave from the point of equilibrium. In the above question,mass attached to a spring of k=18.9N/m follows an oscillatory motion where ,

Angular frequency = [tex]\sqrt{k/m}[/tex] where k is the spring constant and m is the mass

Angular frequency =[tex]\sqrt{18.9/.250[/tex] = 8.69

Therefore ,amplitude is equal to velocity/angular velocity

A=2.89/8.69

=0.33m

Hence , the amplitude of oscillation is 0.33 m.

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