Answer :
Answer:
Explanation:
Total pressure of the mixture = 300 mm Hg
equation of reaction
C₇ H₁₆(g) + 11 O₂ (g) → 7 CO₂(g) + 8 H₂O(g)
partial pressure of heptane = mole fraction heptane × total pressure = 1 / 12 × 300 mm Hg = 25 mm Hg
partial pressure of oxygen = mole fraction oxygen × total pressure = 11 / 12 × 300 mm Hg = 275 mm Hg
After the reaction
total number of mole before the reaction = 12
total number of mole after the reaction = 15
temperature and volume did not change
if 12 to 300 mm Hg
15 will be 15 × 300 / 12 = 375 mm Hg
partial pressure of water vapor = mole fraction of water vapor × 375 mm Hg = 8 / 15 × 375 mm Hg = 200 mm Hg
The pressure of the water vapor on the solution is 200mm Hg. The pressure exerted on the solution by the vapor is known as vapor pressure.
What is vapor pressure?
The pressure exerted on the solution by the vapor is known as vapor pressure.
[tex]{P_{H_2O} = X_{H_2O}\times P_{sol}[/tex]
Where,
[tex]{P_{H_2O}[/tex] - Vapour pressure
[tex]X_{H_2O}[/tex] - Mole fraction of water = 8/15
[tex]P_{sol}[/tex] - Vapour Pressure of solution = 375 mm Hg
Put the values in the formula,
[tex]{P_{H_2O} = \dfrac 8 { 15} \times 375 { \rm \ mm Hg}\\{P_{H_2O} = 200 { \rm \ mm Hg}[/tex]
Therefore, the pressure of the water vapor on the solution is 200mm Hg.
Learn more about vapor pressure,
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