Answer :
Answer:
T(25) = 5.325 min
T (10) = 94.72 min
Explanation:
given data
time taken = 15 min
learning curve = 80%
solution
we use here formula for this task that is
T(n) = T × [tex](No)^{b}[/tex] .............1
here T(n) is time taken for n unit and T is time for 1st hour and No is no of time and b is slope leaning
put here value for 25 we get
T(n) = 15 × [tex]25^{b}[/tex]
b(25) = 0.355
as leaning curve coefficient table
as here with 80% leaning curve
unit timer coefficient = 0.355
so T(25) = 15 × 0.355
T(25) = 5.325 min
and
for 10 exam
leaning curve 80% co efficient is 6.315 from table
so T (10) = 15 × 6.315
T (10) = 94.72 min