Answer :
Answer:
(2, 5 )
Step-by-step explanation:
Given a quadratic in standard form : y = ax² + bx + c : a ≠ 0
Then the x- coordinate of the vertex is
[tex]x_{vertex}[/tex] = - [tex]\frac{b}{2a}[/tex]
y = 3x² - 12x + 17 ← is in standard form
with a = 3 and b = - 12, thus
[tex]x_{vertex}[/tex] = - [tex]\frac{-12}{6}[/tex] = 2
Substitute x = 2 into the function for corresponding value of y
y = 3(2)² - 12(2) + 17 = 12 - 24 + 17 = 5
vertex = (2, 5 )