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The rate of change of speed of the belt is given by 0.06(10 - t) m/s^2, where t is in seconds. The speed of the belt is 0.8 m/s at t = 0. When the normal acceleration of a point in contact with the pulley is 40 m/s^2, determine (a) the speed of the belt; (b) the time required to reach that speed; and (c) the distance traveled by the belt.

Answer :

Answer:

a) speed of belt = 0.8114m/s

b) time required = 0.02secs

c) distance traveled = 0.016m

Explanation:

The detailed and step by step calculation is as shown in the attached files.

${teks-lihat-gambar} olumidechemeng
${teks-lihat-gambar} olumidechemeng

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