Answer :
Answer:
The force that acts on a tossed coin that has reached halfway its maximum height is 50%, whereas, the force that acts on the same coin when it reaches its peak height is 0%.
Explanation:
- When the coin would reach halfway through to the midpoint of it tossing height, it would have consumed half of the energy applied on it, i.e., it would have consumed 50% of the applied force.
- When the coin would reach the peak height, it would cease to move any higher because there would be no energy left in it to move any further. Hence, the force acting on the coin at that point would be 0%.
A Tossed coin when reached halfway the force acts on it is 50% while the force is 0% when it is at its peak height.
Newton's Laws of motion
According to Newton's Laws of motion, the state of motion of an object is directly affected by external forces on it. When the force applied, it is maximum at start and lowest at its peak.
Hence, when tossed coin is at halfway, the force will be 50%, whereas when coin's height is at its peak, the force applied is 0%.
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