Answer :
Explanation:
Expression for the coefficient of thermal expansion is as follows.
[tex]\alpha = \frac{1}{V}(\frac{\Delta V}{\Delta T})[/tex]
where, V = initial volume
[tex]\Delta V[/tex] = Final volume - initial volume
= (712.6 - 873.6) [tex]cm^{3}[/tex]
= -161 [tex]cm^{3}[/tex]
Now, we will calculate the change in temperature as follows.
[tex]\Delta T[/tex] = Final temperature - Initial temperature
= (10 + 273) K - (70 + 273) K
= 283 K - 343 K
= -60 K
Substituting these values into the equation as follows.
[tex]\alpha = \frac{1}{873.6} \times (\frac{161}{60}) K^{-1}[/tex]
= 0.00307 [tex]K^{-1}[/tex]
It is known that for non-ideal gases the value of alpha is 0.366% which is 0.00366 per Kelvin. As it is close to our result, hence the given sample of gas is a non-ideal gas.