Answer :
Answer:
[tex]5 * 10^{10}[/tex]
Explanation:
The question is not complete. Remaining part of the question is as follows - Minimal growth medium for bacteria such as E. coli includes various salts with characteristic concentrations in the mM range and a carbon source. The carbon source is typically glucose and it is used at 0.5% (a concentration of 0.5 g/100 mL). For nitrogen, minimal medium contains ammonium chloride (NH4Cl) with a concentration of 0.1 g/100 mL
How many cells can be grown in a 5 mL culture using minimal medium before the medium exhausts the carbon?
Solution -
We will first find the mass concentration of 0.5 g/100 mL of solution.
[tex]\frac{0.5}{100}[/tex] gram per ml of glucose
The chemical formula of glucose is [tex]C_6H_{12}O_6[/tex]
The molecular weight of glucose molecule is [tex]180[/tex] grams per mole
Now, we will find the number of moles of glucose in a 5 ml medium -
[tex]\frac{\frac{0.5}{100} * 5}{180} \\1.39 * 10^{-4}[/tex] mole
The number of carbon atom in each glucose molecule is equal to six, thus, number of minimal carbon mole is equal to
[tex]1.39 * 10^{-4} * 6\\= 8.34* 10^{-4}[/tex]mole
Number of carbon atoms is equal to
[tex]8.34* 10^{-4} * 6.023 * 10^{23}\\= 5 * 10^{20}\\[/tex] Carbons
One bacteria has [tex]10^{10}[/tex] carbon molecule.Thus, [tex]5[/tex] ml medium will have [tex]5 * 10^{10}[/tex] bacteria