Answer :
Answer:
[tex]9x^{5}y^{5}[/tex] yards.
Step-by-step explanation:
Given that the area of a rectangle (A) is [tex]45x^{8}y^{9}[/tex] square yards.
If the length of the rectangle (L) is given to be [tex]5x^{3}y^{4}[/tex] yards, then we have to find the width (W) of the rectangle in yards.
Now, A = L × W
⇒ [tex]W = \frac{A}{L} = \frac{45x^{8}y^{9}}{5x^{3}y^{4}} = (\frac{45}{5})\times (\frac{x^{8}}{x^{3}}) \times (\frac{y^{9}}{y^{4}}) = 9x^{8 - 3}y^{9 - 4} = 9x^{5}y^{5}[/tex] yards. (Answer)