Answer :
Answer:
x = 0 , y = 0 , z = -3
Step-by-step explanation:
Solve the following system:
{x - 6 y + 4 z = -12 | (equation 1)
x + y - 4 z = 12 | (equation 2)
2 x + 2 y + 5 z = -15 | (equation 3)
Swap equation 1 with equation 3:
{2 x + 2 y + 5 z = -15 | (equation 1)
x + y - 4 z = 12 | (equation 2)
x - 6 y + 4 z = -12 | (equation 3)
Subtract 1/2 × (equation 1) from equation 2:
{2 x + 2 y + 5 z = -15 | (equation 1)
0 x+0 y - (13 z)/2 = 39/2 | (equation 2)
x - 6 y + 4 z = -12 | (equation 3)
Multiply equation 2 by 2/13:
{2 x + 2 y + 5 z = -15 | (equation 1)
0 x+0 y - z = 3 | (equation 2)
x - 6 y + 4 z = -12 | (equation 3)
Subtract 1/2 × (equation 1) from equation 3:
{2 x + 2 y + 5 z = -15 | (equation 1)
0 x+0 y - z = 3 | (equation 2)
0 x - 7 y + (3 z)/2 = -9/2 | (equation 3)
Multiply equation 3 by 2:
{2 x + 2 y + 5 z = -15 | (equation 1)
0 x+0 y - z = 3 | (equation 2)
0 x - 14 y + 3 z = -9 | (equation 3)
Swap equation 2 with equation 3:
{2 x + 2 y + 5 z = -15 | (equation 1)
0 x - 14 y + 3 z = -9 | (equation 2)
0 x+0 y - z = 3 | (equation 3)
Multiply equation 3 by -1:
{2 x + 2 y + 5 z = -15 | (equation 1)
0 x - 14 y + 3 z = -9 | (equation 2)
0 x+0 y+z = -3 | (equation 3)
Subtract 3 × (equation 3) from equation 2:
{2 x + 2 y + 5 z = -15 | (equation 1)
0 x - 14 y+0 z = 0 | (equation 2)
0 x+0 y+z = -3 | (equation 3)
Divide equation 2 by -14:
{2 x + 2 y + 5 z = -15 | (equation 1)
0 x+y+0 z = 0 | (equation 2)
0 x+0 y+z = -3 | (equation 3)
Subtract 2 × (equation 2) from equation 1:
{2 x + 0 y+5 z = -15 | (equation 1)
0 x+y+0 z = 0 | (equation 2)
0 x+0 y+z = -3 | (equation 3)
Subtract 5 × (equation 3) from equation 1:
{2 x+0 y+0 z = 0 | (equation 1)
0 x+y+0 z = 0 | (equation 2)
0 x+0 y+z = -3 | (equation 3)
Divide equation 1 by 2:
{x+0 y+0 z = 0 | (equation 1)
0 x+y+0 z = 0 | (equation 2)
0 x+0 y+z = -3 | (equation 3)
Collect results:
Answer: {x = 0 , y = 0 , z = -3