Answer :
Answer:
C.
A
Explanation:
Question 1
When a third resistor is added in parallel to the first two. The effective resistance of the circuit increases R_eq. When the resistance is increased in a circuit while the battery provides a constant voltage the current decreases as per Ohm's Law:
I = V / R_eq
Current and effective resistance are inversely proportional. Hence, the current in the battery decreases.
Question 2
The terminal voltage remains the same because the amount of push required to move electrons in a path remains same. Adding more paths would not require more push, unless resistance is added in the same path i.e series. Hence, terminal voltage of the battery remains the same.