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You conduct an experiment in which you measure the temperature (T) and volume (V) of a mysterious sphere of gas at several different temperatures.
The sphere can expand or shrink to any volume without changing the pressure of the gas inside.
As a result of your experiment, you find that the volume (V) of the gas divided by its temperature (T) is always equal to 1.75.
What would the volume (V) of the gas be at a temperature of 300K? (assume the unit for volume is liters)
Show your work and answer the question with a clear statement. Show each step of your calculations for full points. After showing your calculations, answer the question with a clear statement.

Answer :

Edufirst

Answer:

[tex]\large\boxed{\text{The volume of the gas at a temperature of 300K is 575 liters}}[/tex]

Explanation:

You already know the relation between the volume (V) of the gas and its temperature (T):

           [tex]V/T=1.75[/tex]

The units of V is liters and of T is Kelvin (K).

Thus, the units of the constant 1.75 is liters/K.

Hence, to find the volume (V) of the gas at a temperature (T) of 300 K, you just must solve for V and substitute the temperature to compute V:

  • Multiply both sides by T:

         [tex]V=1.75T[/tex]

  • Substitute T with 300K:

          [tex]V=1.75liters/K\times 300K=575liters[/tex]

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