Answer :
The volume of hydrogen gas produced at STP by reacting 6.52 g of zinc in excess HCl is 2.2 liters.
Explanation:
The volume of one gas depends on temperature and pressure and it is calculated as 22.4 liters at STP.
1 mole of zinc has 65.38 g of mass.
The amount of zinc = (given mass in grams) / (molar mass of Zn)
= 6.52 / 65.38
= 0.099 mol.
The amount of Zn consumed is equal to the amount of H2 produced.
Now, one mole of an ideal gas will occupy 22.4 liters.
Thus H2 will occupy = 22.4 [tex]\times[/tex] 0.099 = 2.2 liters.
The volume of hydrogen gas at STP is 2.2 liters.