Answer :
Answer:
Maximum velocity of a particle on the string is 1.32 m/s
Explanation:
The speed of the wave in string is
[tex]v=\sqrt{\frac{T}{\mu} }[/tex]
where T= 45 N is tension in the string , [tex]\mu=5.5 g/m[/tex] is the linear mass density
[tex]v=\sqrt{\frac{45}{5.5\times 10^{-3}} }\\v=90.45 m/s[/tex]
Maximum velocity for sinusoidal wave is
[tex]V_{max}=A\omega[/tex] where A is the amplitude,
[tex]\omega=2\pi f\\\omega=2\pi \frac{V}{\lambda} \\\omega=2\pi \frac{90.45}{1.5}\\\omega=378.9 rad[/tex]
now
[tex]V_{max}=A\omega\\V_{max}=3.5 \times 10^{-2} \times 378.9\\V_{max}=1.32 m/s[/tex]