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Agent Bond is standing on a bridge, 13m above the road below, and his pursuers are getting too close for comfort. He spots a flatbed truck approaching at 25m/s, which he measures by knowing that the telephone poles the truck is passing are 25m apart in this country. The bed of the truck is 1.5m above the road, and Bond quickly calculates how many poles away the truck should be when he jumps down from the bridge onto the truck, making his getaway. How many poles is it?

Answer :

tatendagota

Answer:

1.5 poles

Explanation:

First, we take the data:

height = 13 m

speed of the truck = 25m/s

poles distance as he sees them = 25 m

bed of truck = 1.5 m

take acceleration dues to gravity, g = 9.81 m/s²

Agent Bond's jump will be 13 - 1.5 = 11.5 m

The jump takes time, t  =  [tex]\sqrt{\frac{2*11.5}{9.81} }[/tex]

                         = 1. 53 sec

 the truck travels and passes poles at a rate of [tex]\frac{25}{25}[/tex] = 1 pole/second

Therefore, he needs to jump just after the truck is 1.53 or approximately 1.5 poles away.

Based on the information given regarding the speed, the time taken will be 1.53 seconds.

Time taken.

From the information given, the height, acceleration due to gravity, and speed of the truck has been given.

Therefore, the time taken for the jump will be:

= (✓2 × ✓11.5) / ✓9.81

= 1.53 seconds.

In conclusion, the correct option is 1.53 seconds.

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